if a^2+b^2+c^2=250,ab+bc+ca=3, find a+b+c
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In the formula
(a+b+c)² =a²+b²+c²+2ab+2bc+2ca
(a+b+c)² =a²+b²+c²+2(ab+bc+ca)
Put the value of a²+b²+c² and ab+bc+ca which is given in the question then
(a+b+c)²= 250+2*3
(a+b+c)²= 256
then , a+b+c= (256)½
Hence a+b+c= 16
Since 16 is the square root of 256.
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