Question

If a
^2+ b
^2+ c
^2= 250 and ab+ bc+ ca= 3, find a + b + c.

Answer 1

we know (a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+BC+ca)

the value of a^2+b^2+c^2 is given as 250 and AB+BC+CA = 3

so the equation becomes,
(a+b+c)^2 = 250 + 2(3)
which gives, (a+b+c)^2 = 256
hence a+b+c = 16 (Ans)

Answer 2

$<b>ANSWER$

$\huge\mathfrak{Given:}$

=>a²+b²+c² = 250

=>ab+ bc+ ca= 3

As we know

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

(a+b+c)² =250+2×3

(a+b+c)² =256

a+b+c =√256

a+b+c =16

$\boxed{\mathbf{a+b+c =16}}$

$\huge\textbf{THANKS \: }$

HAVE A COLLOSAL DAY AHEAD

$\huge\textbf{BE BRAINLY}$