if a^2+b^2+c^2=50 and ab+bc+ca=47find a+b+c
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Answered by
2
Step-by-step explanation:
(a+b+c)² = a²+b²+c²+2ab+2bc+2ca
(a+b+c)²= 50 + 2(47)
(a+b+c)² = 50+94
(a+b+c)²= 144
a+b+c = √144
a+b+c = 12
Answered by
3
Answer:
a^2+b^2+c^2=(a+b+c)^2
so (a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca=50+2(47)
(a+b+c)^2= 50+94
(a+b+c)^2= 144
a+b+c= √144
a+b+c= 12
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