Question

If a^2+b^2+ c^2=89 and (ab+bc+ca)=16 find (a+b-c)

Answer 1

=Answer:

HI

Step-by-step explanation:

Answer 2

Step-by-step explanation:

lets go to formula

(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

this can also write as

(a+b+c)^2 = a^2 + b^2 + c^2 + (ab + bc + ca) + (ab + bc + ca)

then substitute the values

(a+b+c)^2 = 89 + 16 +16

(a+b+c)^2 = 121

(a+b+c)^2 = (11)^2

then

(a+b+c) = 11