If a 2 + b 2 +c 2 =90 and a+b+c= 20, then find the value of ab+bc+ca
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a+b+c = 20
by squaring the both side we get
a2=b2+c2+2(ab+bc+ac) = 400
90+2(ab+ba+ac) = 400
2(ab+bc+ac) = 310
ans - ab+ba+ac = 155
by squaring the both side we get
a2=b2+c2+2(ab+bc+ac) = 400
90+2(ab+ba+ac) = 400
2(ab+bc+ac) = 310
ans - ab+ba+ac = 155
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