Question

If a^2-b^2 is >0 then a>b or a<(-b) true or false

Answer 1

Answer:

Here a > b is true

Step-by-step explanation:

As,

a² - b² > 0

When we send - b² to RHS it becomes positive

=> a² > b²

If the square of a number is greater than the square of another number then, the number will obviously be greater than the other number

Hence proved ,

a > b

Hope this helps uh....!!!!!

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