If a=2, b=3, c=1, d=0, find the numerical value of 3bcd + 5cda – 7dab + abc.
Answers
Answered by
0
Answer:
3×3×1×0 + 5×1×0×2 - 7×0×2×3 + 2×3×1
= 0+0-0+0
= 0
here is you answer
Answered by
2
Answer:
Step-by-step explanation:
3bcd+5cda-7dab +abc
= d(3bc + 5ca - 7ab) + abc
as d=0
abc = 2*3*1 = 6
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