Math, asked by aumikachatter6b, 4 months ago

If a=2, b=3, c=1, d=0, find the numerical value of 3bcd + 5cda – 7dab + abc.​

Answers

Answered by BaniMishra
0

Answer:

3×3×1×0 + 5×1×0×2 - 7×0×2×3 + 2×3×1

= 0+0-0+0

= 0

here is you answer

Answered by zoyaali0704
2

Answer:

Step-by-step explanation:

3bcd+5cda-7dab +abc

= d(3bc + 5ca - 7ab) + abc

as d=0

abc = 2*3*1 = 6

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