Question

If a=2, b=3, c=1, d=0, find the numerical value of 3bcd + 5cda – 7dab + abc.


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Answer 1

Answer:

6

Step-by-step explanation:

substitute all values a, b, c and d.

3bcd = 3×3×1×0

5cda =0

-7dab = 0

abc = 2×3×1 = 6

every term which contains d is 0 as d is 0

Answer 2

Answer:

3×3×1×0=0 + 5×1×0×2=0 - 7×0×2×3=0 + 2×3×1=6

Ans.=6