If a^2=b^3=c^5=d^6 show that logabc to the base d=31/5
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a² = b³
=> 3logb=2loga => logb = 2/3loga
=> a²=c^5
=> 5logc=2loga => logc = 2/5loga
=> d^6= a²
=> logd = 1/3loga
=> logabc/logd = (loga+logb+logc)/logd
=> (loga + 2/3loga + 2/5loga)/(1/3loga)
=> (1+2/3+2/5)/(1/3)
=> ((15+10+6)/15)/(1/3)
=> 31/5
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