If a = 2, b = 3, then find the value of (a^b+b^a)-1
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Answer:
Heya
Given that
a = 2 ; b = 3
(a^b + b^a)^ = -1
= (2^3 + 3^2)^ = -1
= (8 + 9)^ -1
= (17) ^ -1
= 1/17
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