If a = 2+root 3 , find the value of a to the power cube + 1 by a to the power cube.
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Answered by
1
Answer:
x = 2 + √3
1/x = 1/(2 + √3)
= (2 -√3)/(2 +√3)(2 -√3)
= (2 -√3)/(2² -√3²)
= (2 - √3)
hence, x + 1/x = (2+√3)+(2-√3) = 4
x³ + 1/x³ = (x + 1/x)³ -3(x + 1/x)
= (4)³ - 3(4)
= 64 -12
= 52
Answered by
1
Answer:
Step-by-step explanation:
given a=2+√3
we have to find
a^3 +1×a^3
=(2+√3)^3 +1 × (2+√3)^3
= 8+3×√3 +1 ×8+3×√3
= 11 ×√3 +1×11×√3
= 11×√3×11×√3
= 121 × 3
= 363
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