if a = 2 under root 2 + 1 then find the value of a minus 1 by a
Answers
Answered by
3
a=2
so, √1-a
=√1-2 = -1
so, √1-a
=√1-2 = -1
Answered by
3
Hello Mate!
![a = 2 \sqrt{2} + 1 \\ \frac{1}{a} = \frac{1}{2 \sqrt{2} + 1} \\ rationalize \\ \frac{1}{2 \sqrt{2} + 1} \times \frac{2 \sqrt{2} - 1 }{2 \sqrt{2} - 1} \\ \frac{2 \sqrt{2} - 1}{8 - 1} \\ \frac{2 \sqrt{2} - 1}{7} a = 2 \sqrt{2} + 1 \\ \frac{1}{a} = \frac{1}{2 \sqrt{2} + 1} \\ rationalize \\ \frac{1}{2 \sqrt{2} + 1} \times \frac{2 \sqrt{2} - 1 }{2 \sqrt{2} - 1} \\ \frac{2 \sqrt{2} - 1}{8 - 1} \\ \frac{2 \sqrt{2} - 1}{7}](https://tex.z-dn.net/?f=a+%3D+2+%5Csqrt%7B2%7D+%2B+1+%5C%5C+%5Cfrac%7B1%7D%7Ba%7D+%3D+%5Cfrac%7B1%7D%7B2+%5Csqrt%7B2%7D+%2B+1%7D+%5C%5C+rationalize+%5C%5C+%5Cfrac%7B1%7D%7B2+%5Csqrt%7B2%7D+%2B+1%7D+%5Ctimes+%5Cfrac%7B2+%5Csqrt%7B2%7D+-+1+%7D%7B2+%5Csqrt%7B2%7D+-+1%7D+%5C%5C+%5Cfrac%7B2+%5Csqrt%7B2%7D+-+1%7D%7B8+-+1%7D+%5C%5C+%5Cfrac%7B2+%5Csqrt%7B2%7D+-+1%7D%7B7%7D+)
2_/2 + 1 - ( 2_/2 - 1 ) /7
( 14_/2 + 7 - 2_/2 + 1 ) /7
( 12 _/2 + 8 ) / 7
Hope u got it☺
⭐⭐⭐
2_/2 + 1 - ( 2_/2 - 1 ) /7
( 14_/2 + 7 - 2_/2 + 1 ) /7
( 12 _/2 + 8 ) / 7
Hope u got it☺
⭐⭐⭐
Similar questions
Physics,
8 months ago
Math,
8 months ago
India Languages,
1 year ago
Science,
1 year ago
Social Sciences,
1 year ago