if A = 20 find the value of 5 tan (2A+5) + 12 sin 3A /2 cos 3A- 3 cot Square 3A
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A = 20
5 tan (2A + 5) + 12sin3A/2 cos3A - 3cot^2 3A
= 5 tan [(2*30) + 5] + 12sin(3*20 / 2) * cos (3 *20) - 3 cot^2 (3*20)
= 5 tan 65 + 12 sin 30 * cos 60 - 3cot^2 60
= 5 * 2.145 + 12 * 0.5 * 0.5 - 3 *1/3
= 10.725 + 3 - 3
= 10.725 (Ans.)
5 tan (2A + 5) + 12sin3A/2 cos3A - 3cot^2 3A
= 5 tan [(2*30) + 5] + 12sin(3*20 / 2) * cos (3 *20) - 3 cot^2 (3*20)
= 5 tan 65 + 12 sin 30 * cos 60 - 3cot^2 60
= 5 * 2.145 + 12 * 0.5 * 0.5 - 3 *1/3
= 10.725 + 3 - 3
= 10.725 (Ans.)
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