Question

If a=27,b= —10, c=40, show that a-(b-c)=(a-b)-c

Answer 1

Answer:

a+b+2c

C

C

a

b+c+2a

a

b

b

c+a+2b

a+b+2c 0 a b+c+2a a b b c+a+2b

C

a+b+c 0 C 0 -c-a-b a+b+c -(a+b+c) a c+a+2b =

1 0 -1 =(a+b+c) 0 (a+b+c) -(a+b+c) C a c+a+2b

1 = (a + b + c)²0 C 0 1 a -1 -1 c+a+2b

= (a + b + c)² √ 1 (a+c+2b + a) + c(1) =

2(a+b+c)³

it's is not correct but my imagine