if a+2b+3c=0 prove a3 +8b3+27c3=18abc
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a3+8b3+27c3=18abc
Hence it is proved
Hence it is proved
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wkt
a3 +b3+c3-3abc=(a+b+c)(a2+b2+c2 -ab-bc-ca)
a=a,b=2b,c=3c
so by substuting,
a3+8b3+27c3-18abc= 0(a2-4b2-9c2-2ab-6bc-3ca)
a3+8b3+27c3 -18abc=0
a3+8b3+27c3 =18 abc
QED
plz mark as branliest......hope it helped u☺
a3 +b3+c3-3abc=(a+b+c)(a2+b2+c2 -ab-bc-ca)
a=a,b=2b,c=3c
so by substuting,
a3+8b3+27c3-18abc= 0(a2-4b2-9c2-2ab-6bc-3ca)
a3+8b3+27c3 -18abc=0
a3+8b3+27c3 =18 abc
QED
plz mark as branliest......hope it helped u☺
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