Question

If a + 2b + 3c = 63, find maximum value of a^3 × b^5 ×

c. (given a, b and c are positive).

Answer 1

Soory to say but Question is incomplete..

Hope you understand..

Answer 2

Answer:

Step-by-step explanation:

a/3 = 2b /5 = 3c /1 = (a+2b+3c)/(3+5+1) = 63/9 = 7

==> a = 21; b= 35/2 ; c= 7/3

So a^3 × b^5 × c = 21^3 * (35/2)^ 5 * 7/3