If a+2b=9 and ab=7, find the value of a²+4b²
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Step-by-step explanation:-
Given, ab = 7 --- : ( 1 )
a + 2b = 9 ---: ( 2 )
To find : a^2 + 4b^2
⇒ a^2 + ( 2b )^2
If we observe, a^2 + ( 2b )^2 can be obtained if we applying the formula, ( x + y )^2 on a + 2b . So
Formula : ( x + y )^2 = x^2 + y^2 + 2xy
⇒ ( a + 2b ) = 9
Squaring on both sides : -
⇒ ( a + 2b )^ 2= 9^2
⇒ ( a )^2 + ( 2b )^2 + 2( a*2b ) = 81
⇒ a^2 + 4b^2 + 4ab = 81
⇒ a^2 + 4b^2 = 81 - 4ab
∴ a^2 + 4b^2 = 81 - 4ab
But in the question, value of ab is also given And that 7, so
a^2 + 4b^2 = 81 - 4( 7 )
a^2 + 4b^2 = 81 - 28
a^2 + 4b^2 = 53
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