Math, asked by visheshpachouri31, 9 months ago

If a≠2b & a3+8b3=18ab−27 then find the value of a+2b

Answers

Answered by avneetkaur5409
13

Answer:

Step-by-step explanation:

Given, a3+8b3=18ab−27

⇒a3+8b3+27−18ab=0

⇒(a+2b+3)2[(a−2b)2+(2b−3)2+(3−a)2]=0

⇒a+2b+3=0(∵a≠2b)

⇒a+2b=−3

Answered by gymh716
1

Answer:

Step-by-step explanation:

Given, a3 + 863 = 18ab - 27

a + 863 + 27 - 18ab= 0

a + 2b+3 =0 [:a* 26]

a + 2b=-3

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