If a = 2i - 2j - k and b = -4i + 3j - 2k
a.find the angle between the vectors
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we know
a . b = |a| |b| cosθ
|a| = √(2² + 2² + 1²) = √5
|b| = √(4² + 3² + 2²) = √29
a.b = a1b1 + a2b2 + a3b3 = -8 - 6 + 2 = -12
cosθ = -12/√5 .√29
cosθ = -12/√145
θ = cos⁻¹ 12/√145
a . b = |a| |b| cosθ
|a| = √(2² + 2² + 1²) = √5
|b| = √(4² + 3² + 2²) = √29
a.b = a1b1 + a2b2 + a3b3 = -8 - 6 + 2 = -12
cosθ = -12/√5 .√29
cosθ = -12/√145
θ = cos⁻¹ 12/√145
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