Question

If A=2i+7j+3k and B=3i+2j+5k find the component of A along B

Answer 1

Hi______

A=2i+7j+3k

B=3i+2j+5k

now we know that
A.B=|A||B|cosQ

hope u know
_______________
i.i=j.j=k.k=1
i.j=j.k=k.i=0
___________________
use this

A.B=(2i+7j+3k)(3i^+2j^+5k)

we get
A.B=6+14+15=35

we know component/ project A on B=A.B/||B||

now we need to find out magnitude of B
It is
|B|=(3^2+2^2+5^2)^1/2
=(9+4+25)^1/2
(38)^1/2

put in component formula =35/(38)^1/2

hope it help

Answer 2

Explanation:

aditya bhagat

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