Question

If A=2i+7j+3k and B=3i+2j+5k find the component of A along B

Answer 1

Answer:

A=2i+7j+3k

B=3i+2j+5k

now we know that

A.B=|A||B|cosQ

hope u know

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i.i=j.j=k.k=1

i.j=j.k=k.i=0

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use this

A.B=(2i+7j+3k)(3i^+2j^+5k)

we get

A.B=6+14+15=35

we know component/ project A on B=A.B/||B||

now we need to find out magnitude of B

It is

|B|=(3^2+2^2+5^2)^1/2

=(9+4+25)^1/2

(38)^1/2

put in component formula =35/(38)^1/2

Step-by-step explanation: