Question

if a=2i + j -8k and b= i + 3j -4k then find the magnitude of a+b​

Answer 1

Explanation:

a+b = 3i+4j-12k

so magnitude of any 3D vector -

$\sqrt{x.x \: + y.y \: + z.z}$

so here x= 3 , y= 4 , z= -12

so ans= underroot of : -(9+16+144)

:- undereoot of 169

:- 13.

Answer 2

Answer:

If a=2i + j -8k and b= i + 3j -4k then the magnitude of a + b​ = 13.

Explanation:

Given a=2i + j - 8k and b= I + 3j - 4k

then, at that point,

a + b = 2i + j - 8k + I + 3j - 4k

a + b = 3i + 4j - 12k

so magnitude of any 3D vector -

so here x= 3 , y= 4 , z= - 12

so magnitude of a+ b = $\sqrt{9+16+144$

                                    = $\sqrt{169}$

                                    = 13.

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