Math, asked by mendetejasri, 11 months ago

If a=3-2√2 find the value of (a+1/a)^2

Answers

Answered by kithu13
0

Answer:

a = 3 -  \sqrt[2]{2}  \\ {(a +  \frac{1}{a} )}^{2}   \\  \\  = (3 -  \sqrt[2]{2}  + { \frac{1}{3 -  \sqrt[2]{2} } ) }^{2}  \\  \\  =  {(3 -  \sqrt[2]{2)} }^{2}  +  { (\frac{1}{3 -  \sqrt[2]{2} } )}^{2}  + 2 \times (3 -  \sqrt[2]{2} ) \times ( \frac{1}{3 -  \sqrt[2]{2} } )  \\  \\  =( 9  +  8 -  \sqrt[12]{2} ) +  \frac{1}{9  +  8 -  \sqrt[12]{2}  }  + 2 \times 1 \\  \\  = 17 -  \sqrt[12]{2}  +  \frac{1}{17 -  \sqrt[12]{2}}  + 2

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