Question

if a=√3-√2/√3+√2 and b=1/a find value of a2 +b2 -5ab

Answer 1

a2+b2-5ab=a2+b2-2ab-3ab=(a-b)^2-3ab
putting the value of a nd b
ab=a ×1/a=1
putting these values in (a-b)^2-3ab and solve it