If a =3-2 root2, find the value of a squ. + 1/a squ.
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0
Answer:
a=3+2
2
=>
a
1
=
3+2
2
1
=>
a
1
=
3+2
2
1
×
3−2
2
3−2
2
=>
a
1
=
9−8
3−2
2
=>
a
1
=3−2
2
=>so(a+
a
1
)=(3+2
2
+3−2
2
)
=>(a+
a
1
)=6
=>(a+
a
1
)
2
=6
2
squaringbothside
=>a
2
+(
a
1
)
2
+2×a×
a
1
=36
=>a
2
+
a
2
1
=36−2
=>a
2
+
a
2
1
=34
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