if a=3-3 root 3,find a square minus 1 by a square.
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a=3-3√3
S.B.S
a^2=9+27-18√3..........….........(1)
1/a=(-1-√3)/6
S.B.S
1/a^2=1+3/36+2√3/6
=(12+1+4√3)/12
1/a^2=(13+4√3)/12.........(2)
S.B.S
a^2=9+27-18√3..........….........(1)
1/a=(-1-√3)/6
S.B.S
1/a^2=1+3/36+2√3/6
=(12+1+4√3)/12
1/a^2=(13+4√3)/12.........(2)
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