Math, asked by harinath11913, 23 days ago

if A = 3/4÷5/6; B= 3÷[(4÷5) ÷6]; C = [3÷(4÷5)]÷6 ; D=3÷4(5÷6), then which two are same​

Answers

Answered by XxitzCottonCandyxX
1

Answer:-)

A = 9/10

A = 9/10B = 45/2

A = 9/10B = 45/2C = 45/2

A = 9/10B = 45/2C = 45/2D = 5/8

A = 9/10B = 45/2C = 45/2D = 5/8Step-by-step explanation:

A = 9/10B = 45/2C = 45/2D = 5/8Step-by-step explanation:A = 3/4÷5/6

A = 9/10B = 45/2C = 45/2D = 5/8Step-by-step explanation:A = 3/4÷5/6= 9/10

B = 3={(4-5)=6}

B = 3={(4-5)=6}= 3={(4×1/5)÷6)

B = 3={(4-5)=6}= 3={(4×1/5)÷6)= 3÷{4/5÷6}

B = 3={(4-5)=6}= 3={(4×1/5)÷6)= 3÷{4/5÷6}= 3={4/5×1/6}

B = 3={(4-5)=6}= 3={(4×1/5)÷6)= 3÷{4/5÷6}= 3={4/5×1/6}= 3=4/30

B = 3={(4-5)=6}= 3={(4×1/5)÷6)= 3÷{4/5÷6}= 3={4/5×1/6}= 3=4/30= 3×30/4

B = 3={(4-5)=6}= 3={(4×1/5)÷6)= 3÷{4/5÷6}= 3={4/5×1/6}= 3=4/30= 3×30/4= 90/4

B = 3={(4-5)=6}= 3={(4×1/5)÷6)= 3÷{4/5÷6}= 3={4/5×1/6}= 3=4/30= 3×30/4= 90/4= 45/2

C = [3 (4+5)=6]

C = [3 (4+5)=6]= [3=(4x1/5)+6]

C = [3 (4+5)=6]= [3=(4x1/5)+6]= [3+4/5÷6]

C = [3 (4+5)=6]= [3=(4x1/5)+6]= [3+4/5÷6]= [3+4/5x1/6]

C = [3 (4+5)=6]= [3=(4x1/5)+6]= [3+4/5÷6]= [3+4/5x1/6]= [3+4/30]

C = [3 (4+5)=6]= [3=(4x1/5)+6]= [3+4/5÷6]= [3+4/5x1/6]= [3+4/30]= [3×30/4]

C = [3 (4+5)=6]= [3=(4x1/5)+6]= [3+4/5÷6]= [3+4/5x1/6]= [3+4/30]= [3×30/4]= 90/4

C = [3 (4+5)=6]= [3=(4x1/5)+6]= [3+4/5÷6]= [3+4/5x1/6]= [3+4/30]= [3×30/4]= 90/4= : 45/2

D = 3-4(5÷6)

D = 3-4(5÷6)= 3×1/4(5×1/6)

D = 3-4(5÷6)= 3×1/4(5×1/6)= 3/4(5/6)

D = 3-4(5÷6)= 3×1/4(5×1/6)= 3/4(5/6)= 5/8

Hope it's help !!

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