Question

if A(-3, 5), B(-2, -7), C(1, -8) and D(6,3) are the vertices of a quadrilateral ABCD, find its area

Answer 1

in triangle ABD,
Area of triangle 
=1/2[-3(-7-3)-2(3-5)+6(5+7)
= 1/2 [-3×-10 -2×-2 +6×12]
=1/2 × 30 +4 +72
=1/2×106
=53cm
in triangle BCD
area of triangle
=1/2 [-2(-8-3)+1(3+7)+6(-7+8)
=1/2[-2×-11 +10+6]
=1/2×22+10+6
=1/2×38
=19 cm

so,area of quadilateral=area of triangle ABD+area of triangle BCD
=53+19 = 72 cm²

Answer 2

a b is equal to route packet 1 - 2 + 3 Kavali square + 7 - 7 - 5 whole square equal to root 1 Kaho squared plus 12 squared is equal to 1 + 144 is equal to root 145 BC is equal to root 1 + 2 ka whole square +