Question

If A(-3,5), B(-2, -7). C(1, -8) and D(6,3) are the vertices of a quadrilateral ABCD, find its area.​

Answer 1

Answer:

i hope its correct answer and helpful

Step-by-step explanation:

Let A(2, -1), B(3 ,4), C(-2, 3) and D(-3, -2) Then we have, Length of AB = √[(3 – 2)2 + (4 – (-1))2] = √[(1)2 + (5)2] = √[1 + 25] = √26 units Length of BC = √[(3 – (-2))2 + (4 – 3)2] = √[(5)2 + (1)2] = √[25 + 1] = √26 units Length of CD = √[(-2 – (-3))2 + (3 – 2)2] = √[(-5)2 + (1)2] = √[25 + 1] = √26 units Length of AD = √[(-3 – 2)2 + (-2 – (-1))2] = √[(-5)2 + (-1)2] = √[25 + 1] = √26 units As AB = BC = CD = AD We can say that, Quadrilateral ABCD is a rhombus.Read more on Sarthaks.com - https://www.sarthaks.com/658499/show-that-the-quadrilateral-whose-vertices-are-2-1-3-4-2-3-and-3-2-is-a-rhombus

Answer 2

Answer:

Area of the quadrilateral ABCD,

A = 102sq. units

refer to the attachment