Math, asked by ayushsalunkhe06, 6 hours ago

If A(3, 8), B(4, –2) and C(5, –1) are the vertices of ABC. Then, its area is

(a) 28 1
/2
sq. units
(b) 37 1/2
sq. units
(c) 57 sq. units
(d) 75 sq. units​

Answers

Answered by harshchhawal233
0

Answer:

Here (x

1

=3,y

1

=8);(x

2

=−4,y

2

=2);(x

3

=5,y

3

=−1)

Ar(△ABC)=

2

1

[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)]

=

2

1

[3(2+1)−4(1−8)+5(8−2)]=

2

1

(9+36+30)=

2

75

=37

2

1

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