If A(3, 8), B(4, –2) and C(5, –1) are the vertices of ABC. Then, its area is
(a) 28 1
/2
sq. units
(b) 37 1/2
sq. units
(c) 57 sq. units
(d) 75 sq. units
Answers
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0
Answer:
Here (x
1
=3,y
1
=8);(x
2
=−4,y
2
=2);(x
3
=5,y
3
=−1)
Ar(△ABC)=
2
1
[x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)]
=
2
1
[3(2+1)−4(1−8)+5(8−2)]=
2
1
(9+36+30)=
2
75
=37
2
1
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