If a=3 and b=-2 then find the value of
a^a+b^b
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Answered by
86
given,
a=3,b=-2
a^a+b^b
=3³+(-2)^(-2)
=27+(1/-2)^2
=27+1/4
=109/4
a=3,b=-2
a^a+b^b
=3³+(-2)^(-2)
=27+(1/-2)^2
=27+1/4
=109/4
Answered by
13
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