If a=3 and d=2 then express the progression in A.P
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Answer:
a
3
=15,s
10
=125
a
3
=a+(3−1)d
15=a+2d
a=15−2d
s
10
=
2
10
[2a+(10−1)d]
125=5[2a+9d]
25=2a+9d
25=2(15−2d)+9d
25=30−4d+9d
5d=−5
d=−1
a=15−2×(−1)
a=17
a
10
=a+(10−1)(−1)
a
10 =17−9
a
10
=26
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