If a=3 and t6=27,find the sum of the first sixth term of the Ap
Answers
Answered by
12
Answer:
S6 = 90
Step-by-step explanation:
hello friend
given a = 3 which means first term
and t6 = 27 which means sixth term
generally tn = a + (n-1)d
given t6 = 27
substitute t = 6 in tn = a + (n-1)d
which means t6 = a + 5d
a + 5d = 27
3 + 5d = 27
5d = 24
d = 24/5
where d is common difference in ap
to first sum of first six terms
sum of n terms of an ap is Sn = n/2[2a+(n-1)d]
we have to find S6
S6 = 6/2 [ 2(3)+(6-1)24/5]
= 3[ 6 + 5 × 24/5]
= 3[ 6 + 24]
= 3(30)
= 90
hope it helps you
mark me brainliest if you like my explanation and answer
Answered by
31
Answer:
6/2(3+27). =3(30). Therefore, the sum of first six terms of an AP is 90
hope it is helpful
Similar questions