Question

If a=3 b= 1 and c =(-2) find the value of a2+b2+c2+2ab+2ab+2ca
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Answer 1

Answer:

= 3²+1²+(-2)²+2×3×1+2×3×1+2×-2×3

= 9+1+4+6+6-12

= 14+12-12

= 14

Answer 2

Answer:

4

Step-by-step explanation:

Given,

a = 3

b = 1

c = - 2

To find : a^2 + b^2 + c^2 + 2ab + 2bc + 2ca = ?

a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

= ( a + b + c )^2

= ( 3 + 1 + ( - 2 ) )^2

= ( 3 + 1 - 2 )^2

= ( 4 - 2 )^2

= 2^2

= 4