Question

if a=- 3 ,b=2 and c= -1 then find the value of a) a+b-2c b) 3a-4b+6c/abc

Answer 1

$<i>$Given -

a = - 3

b = 2

c = - 1



a) a + b - 2c

= - 3 + 2 - 2 ( - 1 )

= - 3 + 2 + 2

= 1


b) ( 3a - 4b + 6c ) / abc

= [ ( 3 ) ( - 3 ) - ( 4 ) ( 2 ) + ( 6 ) ( - 1 ) ] / ( - 3 ) ( 2 ) ( - 1 )

= ( - 9 - 8 - 6 ) / 6

= - 23 / 6

Answer 2

Answer:

Step-by-step explanation:

a+b-2c=-3+2+2=1

3a-4b+6c/abc=(-9-8-6) /6=-23/6