Question

if a=3,b= -2 andc = 4 find the value of 3a²b+5ab²+2abc​

Answer 1

Answer:

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Given ,

⇨ a = ( 3 )

⇨ b = ( - 2 )

⇨ c = ( 4 )

$3 {a}^{2} b + 5a {b}^{2} + 2abc \\ \\ = 3 {(3)}^{2} ( - 2) + 5( 3) {( - 2)}^{2} + 2(3)( - 2)(4) \\ \\ = 3 \times 9 \times ( - 2) + 15 \times 4 + 6( - 8) \\ \\ = 27 \times ( - 2) + 60 + ( - 48) \\ \\ = - 54 + 60 - 48 \\ \\ = 6 - 48 \\ \\ = - 42$

⇢ hope this much helps uh ⇠

Answer 2

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Given: a=3, b= -2, c=4

3a²b+5ab²+2abc

3 (3)²+ (-2)+4 (3)(-2)²+2 (3)(-2)(4)

3 (9)+2 (3)(4)+2 (-24)

27+2 (12) -48

27+24-48= 3

Hope it helps you.....