If a = 3, b = -2, c = -1, verify that
(a) b × (a + c) = b × a + b × c
(b) b × c × a = a × b × c = c × a × b
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Hey There !
Here's The Answer
____________________________
Given :
- a = 3
- b = -2
- c = -1
Properties Used :
- BODMAS - Div/Multiply then add/sub.
- Commutative property of multiplication, i.e. ( a × b = b × a )
1. b × (a + c) = b × a + b × c
• Taking L.H.S.
=> b × ( a + c )
=> -2 × ( 3 - 1 )
=> -2 × ( 2 )
=> - 4
• Taking R.H.S.
=> b × a + b × c
=> ( b × a ) + ( b × c )
=> ( -2 × 3 ) + ( -2 × -1 )
=> -6 + 2
=> -4
• Hence, L.H.S. = R.H.S.
2. b × c × a = a × b × c = c × a × b
• Taking L.H.S.
=> b × c × a
=> -2 × -1 × 3
=> 2 × 3
=> 6
• Taking Mid.
=> a × b × c
=> 3 × -2 × -1
=> -6 × -1
=> 6
• Taking R.H.S.
=> c × a × b
=> -1 × 3 × -2
=> -3 × -2
=> 6
• L.H.S. = MID = L.H.S.
• Hence verified
Hope It Helps.
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