Question

if a/3=b/8 then (a+3):(b+8) is equal to​

Answer 1

Answer:

If a/3 = b/8

Then find common multiple between 3 and 8 it is 24

=24/3=24/8

So a is 8 and b is 3

=(8+3)(3+8)

=11×11=121

Answer 2

Answer:

given

a/3=b/8

here,

a=3b/8

substitute in the question

$\frac{a + 3}{b + 8} = \frac{ \frac{3b}{8} + 8}{b + 8}$

$= \frac{ \frac{3b + 64}{8} }{b + 8 } \\ \\ = \frac{3b + 64}{8b + 64}$

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