Question

If
A=35°, B =15° and C =40°
then
the value of
tanA.tanB +tanB.tanC +tanC.tanA​

Answer 1

Answer:

Step-by-step explanation:

Given A=35

0

, B=15

0

and C=40

0

,

tan(A+B+C)=tan(

2

π

​

)=∞

We know that tan(A+B+C)=

1−tanAtanB−tanBtanC−tanCtanA

tanA+tanB+tanC−tanAtanBtanC

​

⇒ denominator =0

∴tanAtanB+tanBtanC+tanCtanA=1