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n=5 terms
Sum= 120 : n/2(2a +(n-1)d)
=5/2(2a+4d)
=5(a+2d)=120
a+2d=24.....................................(1)
Given 5th term is 6 more that sum of first 2 terms :
sum of first 2 terms : a+a+d = 2a+d
5th term : a+ 4d
given : a+4d = 2a+d+6
:::: a-3d=-6.....................................(2)
Solve 1 and 2
a+2d=24
-a+3d=+6
5d=30
d=6
a=12
Thus terms of ap are : 12, 18, 24, 30, 36
Hope this helps!!!!
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