Question

If A = 3a – 2b , B = -2a + 3b and C = -a-b , then find A + B + C.. pls solve it so that i can understand …

Answer 1

Answer:

The answer is 0

Step-by-step explanation:

Given, $A=3a-2b,B=-2a+3b,C=-a-b$

Therefore

$A+B+C=(3a-2b)+(-2a+3b)+(-a-b)$

                  $=3a-2b-2a+3b-a-b$, remove the brackets

                  $=(3a-2a-a)+(-2b+3b-b)$, write like terms together

                  $=(3a-3a)+(-3b+3b)\\=0+0=0$  

Answer 2

Answer:0

Step-by-step explanation: