Math, asked by bgkbs7731, 8 months ago

If a+3b=5 find a3+27b3+45ab

Answers

Answered by teju2161
2

Solution:

Given a+2b = 5 ----(1)

To prove:

a³+8b³+30ab=125

Explanation:

On cubeing equation (1) , we get

(a+2b)³ = 5³

=> a³+(2b)³+3×a×2b×(a+2b)=125

/we know the algebraic identity:

=> a³+8y³+6ab×5 = 125

/* From equation (1) , we get */

=> a³+8y³+30ab = 125

done by TEJU

Answered by bishh65
1

Answer:

Answer 125

Step-by-step explanation:

One hundred twenty five

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