if a+3b=6 and ab=3 find value a2+9b2 is?
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Answered by
1
ab = 3
a = 3/b
a+3b = 6
3/b+3b = 6
3+3b² = 6b
3b²-6b+3 = 0
b²-2b+1 = 0
(b-1)² = 0
b-1 = 0
b = 1
a = 3/b
a = 3/1
a = 3
a²+9b²
= (3)²+9(1)²
= 9+9
=
a = 3/b
a+3b = 6
3/b+3b = 6
3+3b² = 6b
3b²-6b+3 = 0
b²-2b+1 = 0
(b-1)² = 0
b-1 = 0
b = 1
a = 3/b
a = 3/1
a = 3
a²+9b²
= (3)²+9(1)²
= 9+9
=
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Answered by
3
a+3b=6 and,
ab=3
B.T.P:-
(a+3b)2=a2+9b2+2*a*3b
=>6^2=a2+9b2+6ab
=>36=a2+9b2+6*3
=>36-18=a2+9b2
=>a2+9b2=18(ans)
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