Question

if a+3i÷2+ib=1-i show that 5a-7b = 0.......Explain the whole solution please

Answer 1

it's the answer..............

Answer 2

Thank you for asking this question. Here is your answer:

a+3i/ 2 +ib = 1-i

now we will write it as:

a + 3i = (1-i) (2+ib)

a + 3i = 2 + b + i(b-2)

a = 2 + b

3 = b -2

b = 5

a = 7

5a - 7b = 35 - 35 = 0

If there is any confusion please leave a comment below.