Question

if a=3tan theta and b=2cos theta prove a²b²+9b²=36​

Answer 1

Answer:

3tanθ=4

tanθ=

3

4

Thus,

3sinθ−2cosθ

3sinθ+2cosθ

=

3tanθ−2

3tanθ+2

=

3×4/3−2

3×4/3+2

=

2

6

=3

Answer 2

Answer:

Correct option is

C

3

3tanθ=4

tanθ=

3

4

Thus,

3sinθ−2cosθ

3sinθ+2cosθ

=

3tanθ−2

3tanθ+2

=

3×4/3−2

3×4/3+2

=

2

6

=3

Step-by-step explanation:

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