if A=3x square-7x+8,B=x square+8x-3 and C=5x square -3x+2,find the value of B-C-A
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Answered by
4
Hi,
It is given that ,
A = 3x² - 7x + 8 ,
B = x² + 8x - 3 ,
C = 5x² - 3x + 2 ;
B - C - A
= ( x² + 8x - 3 ) - ( 5x² - 3x + 2 ) - ( 3x² - 7x + 8 )
= x² + 8x - 3 - 5x² + 3x - 2 - 3x² + 7x - 8
= ( 1 - 5 - 3 )x² + ( 8 + 3 + 7 )x - 3 - 2 - 8
= -7x² + 18x - 13
I hope this helps you.
: )
It is given that ,
A = 3x² - 7x + 8 ,
B = x² + 8x - 3 ,
C = 5x² - 3x + 2 ;
B - C - A
= ( x² + 8x - 3 ) - ( 5x² - 3x + 2 ) - ( 3x² - 7x + 8 )
= x² + 8x - 3 - 5x² + 3x - 2 - 3x² + 7x - 8
= ( 1 - 5 - 3 )x² + ( 8 + 3 + 7 )x - 3 - 2 - 8
= -7x² + 18x - 13
I hope this helps you.
: )
Answered by
0
A=3x^2-7x+8
B=x^2+8x-3
C=5x^2-3x+2
B-C-A
=x^2+8x-3-5x^2+3x-2-3x^2+7x-8
= -7x^2+18x-13
hope this helps ...
B=x^2+8x-3
C=5x^2-3x+2
B-C-A
=x^2+8x-3-5x^2+3x-2-3x^2+7x-8
= -7x^2+18x-13
hope this helps ...
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