Question

if a (4,1),b(-2,3)and c(0,5)and vertices of triangle abc and ad is its median then the coordinates of midpoint of side bc are​

Answer 1

Given :   a (4,1),b(-2,3)and c(0,5) are vertices of triangle abc

ad is the median

To Find :  coordinates of midpoint of side bc

Solution:

Ad is the mid point

hence d is the mod point of bc

coordinated of d = midpoint of side bc

b(-2,3)and c(0,5)

d = ( -2 + 0)/2 , ( 3 + 5)/2

=> d =  -1 , 4

Hence coordinates of midpoint of side bc are ( - 1,4)

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Answer 2

Step-by-step explanation:

Given: If A(4,1),B(-2,3) and C(0,5)and vertices of triangle ABC and AD is its median.

To find:Coordinates of midpoint of side BC are ?

Solution:

Tip: Mid-point formula

if $(x_1,y_1)$ and $(x_2,y_2)$ are the end points of a line segment, then midpoint of this line segment is $\left(\bold{\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}}\right)$.

Step 1: We know that median AD joins Vertex A and Mid-point of BC.

Step 2: Apply mid-point formula

B(-2,3) and C(0,5)

$D\left(\frac{-2+0}{2},\frac{3+5}{2}\right)$

$D\left(\frac{-2}{2},\frac{8}{2}\right)$

D(-1,4)

Final answer:

Midpoint of BC is D(-1,4)

Hope it helps you.

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