Question

If A= (4, -5) and B= (7 ,-9) what is the length of AB

Answer 1

under root of( x2-x1)²+(y2-y1)²

= 4 = x1,-5 = y1,7= x2,-9 = y2

√(7-4)²+(-5-(-9))²

√3²+4² = √9+16 = √25 = 5......

Answer 2

we have given that, x1=4, y1=-5, x2=7, y2=-9

$ab = \sqrt{(4 - 7) {}^{2} +( - 5 - ( - 9)) {}^{2} } \\ ab = \sqrt{( - 3) {}^{2} +( - 5 + 9) {}^{2} } \\ ab = \sqrt{9 + 16} \\ ab = \sqrt{25} \\ab = 5 \\ i \: hope \: that \: will \: help \: you \: dear$