Question

if A(4,9),B(2,3),C(6,5)are verticle of triangle of abc then the lenght of median through C​

Answer 1

Answer:

Answer:

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Step-by-step explanation:

OPOSITE point of C = AB

midpoint of AB = (3,6)

C=(6,5) midpoint AB =(3,6)

d = \sqrt{(6-3) ^{2} +{5-6}^2

$d =\sqrt{3^2 + 1} \\ </p><p></p><p>d= \sqrt{10 }</p><p></p><p>$

Answer 2

Answer:

If A(4,9),B(2,3),C(6,5) are vertices of triangle of abc then the length of median through C​ is root 10.

Step-by-step explanation:

given:

• The vertices of triangle are  ABC A(4,9), B(2,3),C(6,5).
• We have to find the length of median through C.
• Opposite point of C= AB
• Midpoint of AB is (3,6)
• C=(6,5)
• Distance= $\sqrt{(6-3^{2} )+5-6^{2} }$

• Distance=$\sqrt{3^{2}+1 }$
• Distance=$\sqrt{10}$

If A(4,9),B(2,3),C(6,5) are vertices of triangle of abc then the length of median through C​ is root 10.