Question

If a/4-a+b/4-b+c/4-c =1 prove that 1/4-a+1/4-b+1/4-c=1​

Answer 1

1/4-a+1/4-b+1/4-c=1

Step-by-step explanation:

given

$a/4-a+b/4-b+c/4-c=1$

add 1 on each term both side

$\left ( a/4-a \right )+1+\left ( b/4-b \right )+1+\left ( c/4-c \right )+1=1+1+1+1$

then taking LCM

$\left ( a+4-a \right )/4-a+\left ( b+4-b \right )/4-b+\left ( c+4-c \right )/4-c=4$

here  a,b,c cancel and 4 is left each term

$4\left ( 1/4-a+1/4-b+1/4-c \right )=4$

taking 4 as a common and cancel both side  then we get required solution

$1/4-a+1/4-b+1/4-c=1$

hence proved